Test Index

NCERT Class XI Chemistry Structure of Atom Solutions

© examsnet.com
Question : 1 of 67
Marks: +1, -0
(i) Calculate the number of electrons which will together weigh one gram.
(ii) Calculate the mass and charge of one mole of electrons.
Solution:  
(i) Mass of an electron is 9.109 × 10−3110^{-31} kg.
1 g or 10−310^{-3} kg = 19.109×10−31×10−3\frac{1}{9.109 \times 10^{-31}} \times 10^{-3} electrons = 0.1098 × 102810^{28} electrons
= 1.098 × 102710^{27} electrons
(ii) Mass of 1 electron = 9.109 × 10−3110^{-31} kg
Mass of 1 mole of electrons = 9.109 × 10−3110^{-31} × 6.022 × 102310^{23} = 5.480 × 10−710^{-7} kg
Charge of 1 electron = 1.602 × 10−1910^{-19} C
Charge of 1 mole of electrons = 1.602 × 10−1910^{-19} × 6.022 × 102310^{23} C = 9.647 × 10410^{4} C
© examsnet.com
Go to Question: