Test Index

NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

© examsnet.com
Question : 31 of 36
Marks: +1, -0
How many significant figures should be present in the answer of the following calculations?
(i) 0.02856×298.15×0.1120.5785\frac{0.02856 \times 298.15 \times 0.112}{0.5785}
(ii) 5 × 5.364
(iii) 0.0125 + 0.7864 + 0.0215
Solution:  
(i) 0.02856×298.15×0.1120.5785\frac{0.02856 \times 298.15 \times 0.112}{0.5785} = 0.95369830.5785\frac{0.9536983}{0.5785} = 1.6485711
Correct answer = 1.64
1.64 has 3 significant figures.
(ii) 5 × 5.364 = 26.82
26.82 has 4 significant figures.
(iii) 0.0125 + 0.7864 + 0.0215 = 0.8204
0.8204 has 4 significant figures.
© examsnet.com
Go to Question: