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NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

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Question : 22 of 36
Marks: +1, -0
If the speed of light is 3.0 × 108ms–110^8 m s^{–1}, calculate the distance covered by light in 2.00 ns.
Solution:  
Speed of light = 3.0 × 108ms–110^8 m s^{–1}
Distance covered by light in 2.00 ns = 3.0 × 10810^8 × 2 × 10–910^{–9}
= 6.00 × 10–110^{–1} m = 0.600 m
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