Test Index

NCERT Class XI Chemistry Organic Chemistry Some basic principles and Techniques Solutions

© examsnet.com
Question : 2 of 40
Marks: +1, -0
Indicate the s and p bonds in the following molecules :
C6H6,C6H12,CH2Cl2\mathrm{C_6H_6} , \mathrm{C_6H_{12}},\mathrm{CH_2Cl_2} , CH2=C=CH2\mathrm{CH_2} = \mathrm{C} = \mathrm{CH_2} , CH3NO2,HCONHCH3\mathrm{CH_3NO_2} , \mathrm{HCONHCH_3}
Solution:  
The σ and π bonds are indicated below :
(i)
(ii) C6H12\mathrm{C_6H_{12}} can be either :
(a) Straight chain compound
H3C−H2C−H2C−HC=CH−CH3\mathrm{H_3C-H_2C-H_2C-HC=CH-CH_3}
H−σCσ∣Hσ∣H−σCσ∣Hσ∣H−σCσ∣Hσ∣H−σCσ∣H=σπCσ∣H−σCσ∣Hσ∣H−σH\mathrm{H} - {}^\sigma \overset{\sigma\vert{}^\mathrm{H}}{\underset{\sigma\vert_\mathrm{H}}{\mathrm{C}}} - {}^\sigma \overset{\sigma\vert{}^\mathrm{H}}{\underset{\sigma\vert_\mathrm{H}}{\mathrm{C}}} - {}^\sigma \overset{\sigma\vert{}^\mathrm{H}}{\underset{\sigma\vert_\mathrm{H}}{\mathrm{C}}} - {}^\sigma \underset{\sigma\vert_\mathrm{H}}{\mathrm{C}} = {}^{\underset{\pi}{\sigma}} \overset{\sigma\vert{}^\mathrm{H}}{\mathrm{C}} - {}^\sigma \overset{\sigma\vert{}^\mathrm{H}}{\underset{\sigma\vert_\mathrm{H}}{\mathrm{C}}} - {}_{\sigma} \mathrm{H}
12 C-H σ - bonds
5 C-C σ - bonds
1 C-C π - bond
Other straight chain isomers will also have the same no. of σ and π bonds.
(ii)
6 C-C σ bonds
12 C-H σ bonds
Other cyclic isomers will also have sam no. of σ and π - bonds.
(iii)
2 C-H σ bonds
2 C-Cl σ bonds
(iv)
4 C-H σ bonds
2 C-C σ bonds
2 C-C π bonds
(v)
3 C-H σ bonds
1 C-N σ bond
1 N-O σ bond
1 N-O π bond
(vi)
4C-H σ bonds
1 N-H σ bond
1 C-O π bond
1C-O σ bond
2 C-N σ bonds
© examsnet.com
Go to Question:
Prev Question
Next Question