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NCERT Class XI Chemistry Hydrocarbons Solutions

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Question : 5 of 25
Marks: +1, -0
An alkene A on ozonolysis gives a mixture of ethanal and pentan-3- one. Write the structure and IUPAC name of A.
Solution:  
(A)Alkene(A)_{\text{Alkene}} →ozonolysis\xrightarrow{\text{ozonolysis}}
CH3−CHOEthanal+O=C∣CH2∣CH3C∣CH2∣CH3\underset{\text{Ethanal}}{\mathrm{CH_3-CHO}} + \mathrm{O} = {\overset{\mathrm{CH}_3}{\overset{\vert}{\overset{\mathrm{CH}_2}{\overset{\vert}{\mathrm{C}}}}}}_{\underset{\mathrm{CH}_3}{\underset{\vert}{\underset{\mathrm{CH}_2}{\underset{\vert}{\mathrm{C}}}}}}
Pentan - 3 - one
An alkene when subjected to ozonolysis, cleaves at the double bond and gives rise to carbonyl compounds.
Since, the given compounds here are ethanal and pentan-3-one, the alkene can be predicted to be:
H3C−HC=O+O=C∣CH2∣CH3C∣CH2∣CH3\mathrm{H_3C-HC=O} + \mathrm{O} = {\overset{\mathrm{CH}_3}{\overset{\vert}{\overset{\mathrm{CH}_2}{\overset{\vert}{\mathrm{C}}}}}}_{\underset{\mathrm{CH}_3}{\underset{\vert}{\underset{\mathrm{CH}_2}{\underset{\vert}{\mathrm{C}}}}}}
→
H3C1−CH2=C∣CH2∣CH33−CH24−CH353-Ethylpent-2-ene{\underset{1}{\mathrm{H_3C}}-\underset{2}{\mathrm{CH}}=\underset{3}{\overset{\overset{\mathrm{CH}_3}{\vert}}{\overset{\overset{\mathrm{CH}_2}{\vert}}{\mathrm{C}}}}-\underset{4}{\mathrm{CH_2}}-\underset{5}{\mathrm{CH_3}}}_{\text{3-Ethylpent-2-ene}}
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