NCERT Class XI Chemistry Equilibrium Solutions

Question : 60

Total: 73

The pH of 0.1 M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution.

Solution:

HCNO ⇌ H++CNO−
pH = 2.34 or log [H+] = –2.34 or [H+] = antilog(–2.34) = 4.57 × 10–3M
[CNO–] = [H+] = 4.57 × 10–3M
Ka =

(4.57×10−3)(4.57×10−3)

0.1

= 2.09 × 10−4
α = √

= √

2.09×10−4

0.1

= 0.0457

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