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NCERT Class XI Chemistry Equilibrium Solutions

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Question : 55 of 73
Marks: +1, -0
Calculate the hydrogen ion concentration in the following biological fluids whose pH are given below:
(a) Human muscle-fluid, 6.83
(b) Human stomach fluid, 1.2
(c) Human blood, 7.38
(d) Human saliva, 6.4.
Solution:  
(a) pH = 6.83
∴ [H+][\mathrm{H}^{+}] = antilog(– 6.83) = 1.48 × 10−7 M10^{-7}\,\text{M}
(b) pH = 1.2
∴ [H+][\mathrm{H}^{+}] = antilog(–1.2) = 6.30 × 10−2 M10^{-2}\,\text{M}
(c) pH = 7.38
∴ [H+][\mathrm{H}^{+}] = antilog (– 7.38) = 4.17 × 10−8 M10^{-8}\,\text{M}
(d) pH = 6.4,
∴ [H+][\mathrm{H}^{+}] = antilog(–6.4) = 3.98 × 10−7 M10^{-7}\,\text{M}
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