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NCERT Class XI Chemistry Equilibrium Solutions

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Question : 41 of 73
Marks: +1, -0
The concentration of hydrogen ions in a sample of soft drink is 3.8 × 10−310^{-3} M. What is its pH?
Solution:  
[H+][\mathrm{H}^{+}] = 3.8 × 10−310^{-3} M
pH = – log [H+][\mathrm{H}^{+}] = – log(3.8 × 10−310^{-3}) = 3 log10 – log 3.8 = 3 – 0.5797
pH = 2.4203 ≈ 2.42
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