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NCERT Class XI Chemistry Equilibrium Solutions

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Question : 4 of 73
Marks: +1, -0
Write the expression for the equilibrium constant, KcK_c for each of the following reactions :
(i) 2NOCl(g)2\mathrm{NOCl}_{(g)} ⇌ 2NO(g)+Cl2(g)2\mathrm{NO}_{(g)} + \mathrm{Cl}_{2(g)}
(ii) 2Cu(NO3)2(s)2\mathrm{Cu}(\mathrm{NO}_3)_{2(s)} ⇌ 2CuO(s)+4NO2(g)+O2(g)2\mathrm{CuO}_{(s)} + 4\mathrm{NO}_{2(g)} + \mathrm{O}_{2(g)}
(iii) CH3COOC2H5(aq)+H2O(l)\mathrm{CH_3COOC_2H}_{5(aq)} + \mathrm{H}_2\mathrm{O}_{(l)} ⇌ CH3COOH(aq)+C2H2OH(aq)\mathrm{CH_3COOH}_{(aq)} + \mathrm{C}_2\mathrm{H}_2\mathrm{OH}_{(aq)}
(iv) Fe(aq)3++3OH(aq)−\mathrm{Fe}^{3+}_{(aq)} + 3\mathrm{OH}^{-}_{(aq)} ⇌ Fe(OH)3(s)\mathrm{Fe}(\mathrm{OH})_{3(s)}
(v) I2(s)+5F2(g)\mathrm{I}_{2(s)} + 5\mathrm{F}_{2(g)} ⇌ 2IFe5(g)2\mathrm{IFe}_{5(g)}
Solution:  
(i) KcK_c = [NO(g)]2[Cl2(g)][NOCl(g)]2\frac{[\mathrm{NO}_{(g)}]^{2}[\mathrm{Cl}_{2(g)}]}{[\mathrm{NOCl}_{(g)}]^{2}}
(ii) KcK_c = [CuO(s)]2[NO2(g)]4[O2(g)][Cu(NO3)2(g)]2\frac{[\mathrm{CuO}_{(s)}]^{2}[\mathrm{NO}_{2(g)}]^{4}[\mathrm{O}_{2(g)}]}{[\mathrm{Cu}(\mathrm{NO}_3)_{2(g)}]^{2}} = [NO2(g)]4[O2(g)][\mathrm{NO}_{2(g)}]^{4}[\mathrm{O}_{2(g)}]
(iii) KcK_c = [CH3COOH(aq)][C2H5OH(aq)][CH3COOC2H5(aq)][H2O(l)]\frac{[\mathrm{CH_3COOH}_{(aq)}][\mathrm{C}_2\mathrm{H}_5\mathrm{OH}_{(aq)}]}{[\mathrm{CH_3COOC}_2\mathrm{H}_{5(aq)}][\mathrm{H}_2\mathrm{O}_{(l)}]} = [CH3COOH(aq)][C2H5OH(aq)][CH3COOC2H5(aq)]\frac{[\mathrm{CH_3COOH}_{(aq)}][\mathrm{C}_2\mathrm{H}_5\mathrm{OH}_{(aq)}]}{[\mathrm{CH_3COOC}_2\mathrm{H}_{5(aq)}]}
(iv) KcK_c = [Fe(OH)3(s)][Fe(aq)3+][OH(aq)−03\frac{[\mathrm{Fe}(\mathrm{OH})_{3(s)}]}{[\mathrm{Fe}^{3+}_{(aq)}][\mathrm{OH}^{-}_{(aq)}0^{3}} = 1[Fe(aq)3+][OH(aq)−]3\frac{1}{[\mathrm{Fe}^{3+}_{(aq)}][\mathrm{OH}^{-}_{(aq)}]^{3}}
(v) KcK_c = [IF5(g)]2[I2(s)][F2(g)]5\frac{[\mathrm{IF}_{5(g)}]^{2}}{[\mathrm{I}_{2(s)}][\mathrm{F}_{2(g)}]^{5}} = [IF5(g)]2[F2(g)]5\frac{[\mathrm{IF}_{5(g)}]^{2}}{[\mathrm{F}_{2(g)}]^{5}}
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