Let coordinates of A and B be (a,0) and (0,b) .
∵ The coordinate of a point P(4,−1) on AB divides it in the ratio 1:2 .
i.e., AP:PB=1:2
By using section formula,
‌4=‌

1×0+2×a

1+2

‌[∵x=‌

m1x2+m2x1

m1+m2

]
‌⇒‌‌12=2a⇒a=6
‌‌ and ‌ ‌−1=‌

1×b+2×0

1+2

‌[∵y=‌

m1y2+m2y1

m1+m2

]
‌⇒‌‌−3=b
Hence, Coordinate of A=(6,0)
and Coordinate of B=(0,−3)