ICSE Class X Math 2016 Paper

In the given figure below, $A D$ is a diameter. $O$ is the centre of the circle. $A D$ is parallel to $B C$ and $\angle C B D=32^{\circ}$ . Find:

Question : 9 of 57

Marks: +1, -0

\angle OBD

Solution:

Given :

AD \parallel BC

\; \therefore \;\; \angle ADB = \angle DBC = 32^{\circ}

\;\; \text{ (alternate angles) }\;

\; OB = OD \; \text{ (radii of the circle) }\;

\; \therefore \angle OBD = 32^{\circ}

(angles opposite to equal sides of a triangle)

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