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ICSE Class X Math 2016 Paper

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The table shows the distribution of the scores obtained by 160 shooters in a shooting competition. Use a graph sheet and draw an ogive for the distribution.
(Take 2 cm=102\,\mathrm{cm}=10 scores on the XX axis and 2 c m=20c\,m=20 shooters on the YY-axis).
 Scores  No. of shooters
 0-10  9
 10-20  13
 20-30  20
 30-40  26
 40-50  30
 50-60  22
 60-70  15
 70-80  10
 80-90  8
 90-100  7
Use your graph to estimate the following :
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Question : 30 of 57
Marks: +1, -0
The median.
Solution:  
 Scores  No. of shooters  c.f.
 0-10  9  9
 10-20  13  22
 20-30  20  42
 30-40  26  68
 40-50  30  98
 50-60  22  120
 60-70  15  135
 70-80  10  145
 80-90  8  153
 90-100  7  160
Since, no. of terms, n=160n=160 which is even.
∴     Median     =(  n2)  th    term \therefore\;\; \text{ Median } \;\; = \left(\; \frac{n}{2}\right)^{\; \text{th } \;} \text{ term }
  =(  1602)  th    term \; = \left(\; \frac{160}{2}\right)^{\; \text{th } \;} \text{ term }
  =80   th term \; = 80 \; \text{ th term }
From the graph, median =43.5=43.5
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