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ICSE Class X Math 2016 Paper

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In the given figure PQRSP Q R S is a cyclic quadrilateral PQP Q and SRS R produced meet at TT.
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Question : 25 of 57
Marks: +1, -0
Find SPS P if TP=18 cm,RQ=4 cmT P = 18\,\text{cm}, R Q = 4\,\text{cm} and TR=6 cmT R = 6\,\text{cm}.
Solution:  
In similar triangles â–³TPS\triangle TPS and TRQ
    TPTR=  PSRQ\;\; \frac{T P}{T R} = \; \frac{P S}{R Q}
    186=  PS4\;\; \frac{18}{6} = \; \frac{P S}{4}
  PS=  726\; PS = \; \frac{72}{6}
    =12 cm.\;\; = 12\,\text{cm}.
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