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ICSE Class X Math 2015 Solved Paper

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Three vertices of a parallelogram ABCD taken in order are A(3,6),B(5,10) and C(3, 2) find:
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Question : 9
Total: 52
equation of side AB of the parallelogram ABCD .
Solution:  
Equation of AB :
y−y1‌=‌
y2−y1
x2−x1
(x−x1)
y−6‌=‌
10−6
5−3
(x−3)
y−6‌=‌
4
2
(x−3)
y−6‌=2x−6
2x−y‌=0
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