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ICSE Class X Math 2015 Paper

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Three vertices of a parallelogram ABCDA B C D taken in order are A(3,6),B(5,10)A(3,6), B(5,10) and C(3C(3, 2) find:
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Question : 8 of 52
Marks: +1, -0
length of diagonal BD.
Solution:  
BD  =(51)2+(10+2)2BD \; = \sqrt{(5-1)^2+(10+2)^2}
  =16+144\; = \sqrt{16+144}
  =160\; = \sqrt{160}
  =410   units.  \; = 4 \sqrt{10} \; \text{ units.} \;
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