Construct a triangle A B C with AB=5.5\,{cm} ...

ICSE Class X Math 2015 Paper

Question : 52 of 52

Marks: +1, -0

Construct a triangle

A B C

with

AB=5.5\,\mathrm{cm}

AC=6\,\mathrm{cm}

and

\angle BAC=105^{\circ}

. Hence

(i) Construct the locus of points equidistant from

BA

and

BC

(ii) Construct the locus of points equidistant from

B

and

C

(iii) Mark the point which satisfies the above two loci as

P

. Measure and write the length of PC.

Solution:

Steps of Construction :

(i) Draw a line

AB=5.5\,\mathrm{cm}

(ii) With the help of the point

A

, draw

\angle XAB=105^{\circ}

(iii) Taking radius

6\,\mathrm{cm}

, cut

AC=6\,\mathrm{cm}

and join

C

B

(iv) Draw perpendicular bisector of

BC

and angle of bisector

\angle CBA

; both intersecting at

P

P

is the required point.

PC=4.8\,\mathrm{cm}\;\text{. }\;

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