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ICSE Class X Math 2014 Paper

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Question : 51 of 52
Marks: +1, -0
Prove the identity:
(sinheta+cosheta)(anheta+cotheta)(\sin heta + \cos heta)( an heta + \cot heta) =secheta+cscheta= \sec heta + \csc heta
Solution:  
extL.H.S.=(sinheta+cosheta)(anheta+cotheta)ext{L.H.S.} = (\sin heta + \cos heta)( an heta + \cot heta)
=(sinθ+cosθ)(sinθcosθ+cosθsinθ)= (\sin\theta + \cos\theta) \left( \frac{\sin\theta}{\cos\theta} + \frac{\cos\theta}{\sin\theta} \right)
=(sinθ+cosθ)(sin2θ+cos2θcosθsinθ)= (\sin \theta + \cos \theta) \left( \frac{\sin^2 \theta + \cos^2 \theta}{\cos \theta \sin \theta} \right)
=(sinθ+cosθ)×1cosθsinθ= (\sin \theta + \cos \theta) \times \frac{1}{\cos \theta \sin \theta}
=sinθcosθsinθ+cosθcosθsinθ= \frac{\sin\theta}{\cos\theta \sin\theta} + \frac{\cos\theta}{\cos\theta \sin\theta}
=1cosθ+1sinθ=secθ+cscθ= \frac{1}{\cos \theta} + \frac{1}{\sin \theta} = \sec \theta + \csc \theta
=extR.H.S.= ext{R.H.S.}
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