In the given circuit diagram, the two 15Ω resistor are in series, so their total resistance
R s=15+15=30Ω
Now, Rs and the given 30Ω resistors are in parallel, so the net resistance
‌

1

Rp

‌=‌

1

30

+‌

1

30

‌

1

Rp

‌=‌

1+1

30

=‌

2

30

∴‌‌Rp‌=‌

30

2

=15Ω
So, ‌‌Req=15Ω
We know, ‌‌I=‌

ε

Req+r

∴‌‌I=‌

3.4

15+2

=‌

3.4

17

=0.2A