Test Index

ICSE Class 10 Physics 2023 Paper

© examsnet.com
Question : 57 of 76
Marks: +1, -0
Complete the following nuclear changes :
92238P→..........Q+24He→.... . . . . R+−10e{}_{92}^{238}P \xrightarrow[\text{.....}]{\text{.....}} Q + {}_{2}^{4}\mathrm{He} \xrightarrow[\text{....}]{\text{ . . . . }} R + {}_{-1}^{0}\mathrm{e}
Solution:  
92238P→90234Q+24He→91234R+−10e{}_{92}^{238}P \rightarrow {}_{90}^{234}Q + {}_{2}^{4}\mathrm{He} \rightarrow {}_{91}^{234}R + {}_{-1}^{0}\mathrm{e}
© examsnet.com
Go to Question:
Prev Question
Next Question