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ICSE Class 10 Physics 2022 Paper

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Question : 37 of 45
Marks: +1, -0
Complete and rewrite the following nuclear reaction by filling the blanks.
.....235U→90....Th+24He{}_{. . . . .}^{235}\mathrm{U}\rightarrow{}_{90}^{....}\mathrm{Th}+{}_{2}^{4}\mathrm{He}
Solution:  
Atomic no. of Uranium =90+2=92=90+2=92
Mass no. of Thorium =235−4=231=235-4=231
92235U→90231Th+24He{}_{92}^{235}\mathrm{U}\rightarrow{}_{90}^{231}\mathrm{Th}+{}_{2}^{4}\mathrm{He}
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