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ICSE Class 10 Physics 2022 Paper

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An appliance rated 440W,220V440\,\mathrm{W}, 220\,\mathrm{V} is connected across 220V220\,\mathrm{V} supply.
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Question : 33 of 45
Marks: +1, -0
Calculate the resistance of the appliance.
Solution:  
Let P=VIP = VI and I=  VRI = \;\frac{V}{R}
    P=V2R\because\;\; P = \frac{V^2}{R}
R=  V2PR = \;\frac{V^2}{P}
  =  220×220440\;=\; \frac{220 \times 220}{440}
  =110Ω\;= 110 \Omega
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