ICSE Class 10 Physics 2020 Solved Paper

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The diagram above shows three resistors connected across a cell of e.m.f. 1.8V and internal resistance r. Calculate:
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Question : 53
Total: 67
The internal resistance r.
Solution:  
In the given diagram, 3Ω and 1.5Ω resistor are in parallel.
‌∴‌‌
1
Rp
‌
=‌
1
3
+‌
1
1â‹…5

‌‌
1
Rp
‌
=‌
1+2
3
=‌
3
3

‌∴‌Rp‌=1Ω
Now Rp and 4Ω resistances are in series
∴‌‌Rs=1+4=5Ω
So net external resistance of the circuit =5Ω
‌‌ We know, ‌‌‌I=‌
E
Rext+r

‌⇒‌‌0⋅3=‌
1â‹…8
(5+r)

‌⇒‌‌0.3(5+r)=1.8
‌⇒‌‌(5+r)=6
‌⇒‌‌r=6−5
‌r=1Ω
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