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ICSE Class 10 Physics 2020 Paper

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Question : 24 of 67
Marks: +1, -0
A nucleus 84X202{}_{84}\mathrm{X}^{202} of an element emits an alpha particle followed by a beta particle. The final nucleus is YbY^{b}. Find aa and bb.
Solution:  
  84X202α82P198+24He\;{}_{84}\mathrm{X}^{202} \xrightarrow{-\alpha} {}_{82}\mathrm{P}^{198} + {}_{2}^{4}\mathrm{He}
  82P198β83Y198+10e\;{}_{82}\mathrm{P}^{198} \xrightarrow{-\beta} {}_{83}\mathrm{Y}^{198} + {}_{-1}^{0}\mathrm{e}
Comparing aYb{}_{a}\mathrm{Y}^{b} and 83Y198{}_{83}\mathrm{Y}^{198}; We get
a=83a=83 and b=198b=198.
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