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ICSE Class 10 Physics 2019 Paper

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Question : 70 of 74
Marks: +1, -0
Rewrite and complete the following nuclear reaction by filling in the atomic number of BaB a and mass number of KrK r :
92235U+01n....144Ba+36....Kr+301n_{92}^{235}\mathrm{U}+_{0}^{1}\mathrm{n}\rightarrow_{....}^{144}\mathrm{B a}+_{36}^{....}\mathrm{K r}+3_{0}^{1}\mathrm{n} +   Energy   +\;\text{ Energy }\;
Solution:  
92235U+01n56144Ba+3689Kr_{92}^{235}\mathrm{U}+_{0}^{1}\mathrm{n}\rightarrow_{56}^{144}\mathrm{B a}+_{36}^{89}\mathrm{K r} +301n+   Energy   +3_{0}^{1}\mathrm{n}+\;\text{ Energy }\;
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