Test Index

ICSE Class 10 Physics 2019 Paper

Show Para  Hide Para 
The diagram above shows a circuit with the key kk open. Calculate :
© examsnet.com
Question : 60 of 74
Marks: +1, -0
the current drawn from the cell when the key kk is open.
Solution:  
When the key K{K} is open,
I  =  ER+r  =  3.35+0.5I\;=\;\frac{E}{R+r}\;=\;\frac{3.3}{5+0.5}
  =  3.35.5  =  35=0.6 A\;=\;\frac{3.3}{5.5}\;=\;\frac{3}{5}=0.6\,\mathrm{A}
© examsnet.com
Go to Question: