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ICSE Class 10 Physics 2019 Paper

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Question : 40 of 74
Marks: +1, -0
If the free end of the string moves through a distance xx , find the distance by which the load is raised.
Solution:  
  ∵       V. R.   =  dEdL\; \because \;\; \;\text{ V. R. }\;=\;\frac{d_E}{d_L}
  ∴    2=  xdL\; \therefore \;\; 2=\;\frac{x}{d_L}
  ⇒    dL=  x2\; \Rightarrow \;\; d_L=\;\frac{x}{2}
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