Calculate the effective resistance across A ... - ICSE Class 10 ...

ICSE Class 10 Physics 2019 Paper

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Question : 26 of 74

Marks: +1, -0

Calculate the effective resistance across

A B

:

Solution:

In the figure,

5 \Omega

and

4 \Omega

are in series, So their resultant will be

5+4

i.e.

9 \Omega

.

Now,

9 \Omega

and

3 \Omega

are in parallel, so their resultant

R_P

is calculated as :

\frac{1}{R_{P}} = \frac{1}{9} + \frac{1}{3}

\frac{1}{R_{P}} = \frac{1+3}{9}

\frac{1}{R_{P}} = \frac{4}{9}

\therefore \;\; R_{P} = \frac{9}{4} = 2.25 \Omega

Now,

8 \Omega

and

2.25 \Omega

are in series,

\therefore \; R_{AB} = 8 + 2.25

= 10.25 \Omega

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