ICSE Class 10 Physics 2018 Solved Paper

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A half metre rod is pivoted at the centre with two weights of 20‌gf and 12‌gf suspended at a perpendicular distance of 6‌cm and 10‌cm from the pivot respectively as shown below.
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Question : 41
Total: 78
Is the rod in equilibrium?
Solution:  
Clockwise moment of force
‌=12‌gf×10‌cm
‌=120‌gf−cm
Anticlockwise moment of force
‌=20‌gf×6‌cm
‌=120‌gf−cm
since, the clockwise moment of force is equal to the anticlockwise moment of force, the rod is in equilibrium
Thus, Yes, the rod is in equilibrium.
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