Test Index

ICSE Class 10 Physics 2018 Paper

© examsnet.com
Question : 28 of 78
Marks: +1, -0
How is the e.m.f. across primary and secondary coils of a transformer related with the number of turns of coil in them?
Solution:  
For a transformer,
e.m.f. across the secondary coil  (Es)e.m.f. across the primary coil  (Ep)\frac{\text{e.m.f. across the secondary coil}\; (E_s)}{\text{e.m.f. across the primary coil}\; (E_p)} =number of turns in the secondary coil  (NS)number of turns in the primary coil  (NP)= \frac{\text{number of turns in the secondary coil}\; (N_S)}{\text{number of turns in the primary coil}\; (N_P)}
or EsEp=NsNp\frac{E_s}{E_p} = \frac{N_s}{N_p}
© examsnet.com
Go to Question:
Prev Question
Next Question