ICSE Class 10 Physics 2017 Paper

A pulley system with $V R=4$ is used to lift a load of $175\,\text{kgf}$ through a vertical height of $15\,\text{m}$ . The effort required is $50\,\text{kgf}$ in the downward direction. $(g=10\,\text{N}\,\text{kg}^{-1})$
Calculate:

Question : 29 of 65

Marks: +1, -0

Work done by the effort.

Solution:

Work done be the effort = Effort

\times d_{E}

\text{ Given : } \text{ Effort } = 50 \text{ kgf}

= 50 \times 10 = 500 \text{ N}

\therefore\ W_{E} = E \times d_{E} = 500 \times 60 \text{ J}

= 30,000 \text{ J}

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