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ICSE Class 10 Physics 2016 Solved Paper

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A battery of emf 12V and internal resistance 2Ω is connected with two resistors A and B of resistance 4Ω and 6Ω respectively joined in series.

Find:
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Question : 61
Total: 73
Current in the circuit.
Solution:  
Given : V=12V, Resistance of A=4Ω, Resistance of B=6Ω, Internal battery resistance =2Ω.

‌ Total Resistance ‌‌=4+6+2
‌=12Ω.
‌ I (current in circuit) ‌‌=‌
‌ e.m.f. ‌
‌ Total resistance ‌

‌=‌
12
12
=1amp.
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