Find the equivalent resistance between ...

ICSE Class 10 Physics 2015 Paper

Question : 29 of 74

Marks: +1, -0

Find the equivalent resistance between points

A

and

B

Solution:

Let

12\ \Omega,\ 6\ \Omega

and

4\ \Omega

are in parallel.

\;\frac{1}{R_p}\;=\;\frac{1}{4}+\;\frac{1}{6}+\;\frac{1}{12}

\;=\;\frac{3+2+1}{12}=\;\frac{6}{12}=\;\frac{1}{2}

R_p\;=2\ \Omega .

Now

2\ \Omega,\ R_p

and

5\ \Omega

are in series.

\because \;\; R_{AB}\;=2+ R_p+5=2+2+5

\;=9\ \Omega .

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