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ICSE Class 10 Physics 2014 Solved Paper

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Question : 27
Total: 66
Find the equivalent resistance between points A and B.
Solution:  
‌ Let ‌‌‌
1
R1
=‌
1
3
+‌
1
3
+‌
1
3
=‌
3
3
=1
∴‌‌R1=1Ω
R2‌=5Ω
‌
1
R3
‌=‌
1
4
+‌
1
6
=‌
3+2
12
=‌
5
12

‌R3=‌
12
5
=2.4Ω

Equivalent resistance between A and B,
R‌=R1+R2+R3
‌=1+5+2.4=8.4Ω.
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