Test Index

ICSE Class 10 Physics 2013 Solved Paper

© examsnet.com
Question : 6
Total: 70
A force is applied on a body of mass 20‌kg moving with a velocity of 40ms−1. The body attains a velocity of 50ms−1 in 2 seconds. Calculate the work done by the body.
Solution:  
‌ Force ‌‌=m‌
(v−u)
t
=‌ m.a. ‌
‌ Displacement ‌‌=‌
(v2−u2)
2a

‌ Work done ‌‌=‌ Force ‌×‌ Displacement ‌
‌=‌ m.a. ‌‌
(v2−u2)
2a

W‌=‌
1
2
m(v2−u2)
W‌=‌
1
2
×20×(502−402)
‌=‌
1
2
×20×900
‌=9000‌Joule.
© examsnet.com
Go to Question:
Prev Question
Next Question