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ICSE Class 10 Physics 2013 Solved Paper

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Question : 21
Total: 70
Calculate the equivalent resistance between the points A and B for the following combination of resistors :
Solution:  
Let 4Ω,4Ω and 4Ω are in series.

R1=4+4+4=12Ω‌. ‌
Now 2Ω,2Ω and 2Ω are in series.

R2=2+2+2=6Ω

Now R1=12Ω,R2=6Ω and 4Ω are in parallel.
‌
1
R3
‌=‌
1
12
+‌
1
4
+‌
1
6

‌=‌
1+3+2
12
=‌
6
12
=‌
1
2

R3‌=2Ω
Now resistance between A and B,5Ω,2Ω and 6Ω are in series.

Resistance between A and B, R=5+2+6 =13Ω
Hence, Equivalent resistance between A and B=13Ω
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