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ICSE Class 10 Physics 2013 Paper

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Question : 63 of 70
Marks: +1, -0
Calculate the power dissipated in the 3Ω3 \Omega resistor.
Solution:  
P  =V⋅I.P\;= V \cdot I.
=I2R= I^2 R
=(0.5)2×3=0.25×3= (0.5)^2 \times 3 = 0.25 \times 3
P  =0.75  watt.  P\;= 0.75 \;\text{watt.}\;
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