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ICSE Class 10 Chemistry 2019 Paper

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SECTION - II
Draw the electron dot structure of :
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Question : 40 of 86
Marks: +1, -0
Sodium chloride     [Na=11,Cl=17]\;\; [ \mathrm{Na}=11, \mathrm{Cl}=17]
Solution:  
Electron dot structure of Sodium
Chloride: NaCl\mathrm{NaCl}
  Na=11=2,8,1\; \mathrm{Na}=11=2,8,1
  Cl=17=2,8,7\; \mathrm{Cl}=17=2,8,7
Na−e−  →Na+\mathrm{Na}-e^{-}\;\rightarrow \mathrm{Na}^{+}
Cl+e−  →Cl−\mathrm{Cl}+e^{-}\;\rightarrow \mathrm{Cl}^{-}
Na++Cl−  →NaCl\mathrm{Na}^{+}+ \mathrm{Cl}^{-}\;\rightarrow \mathrm{NaCl}
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