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ICSE Class 10 Chemistry 2019 Paper

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Question : 22 of 86
Marks: +1, -0
The weight of 102210^{22} atoms of carbon. [C=12.[ C=12., Avogadro's No. =6×1023]=6 \times 10^{23}]
Solution:  
If 6×10236 \times 10^{23} atoms have a weight
=12gm=12 \text{gm}
then 102210^{22} atoms have a weight
  =  12×10226×1023\;=\;\frac{12 \times 10^{22}}{6 \times 10^{23}}
  =  126×10=  1260=0.20gm\;=\;\frac{12}{6 \times 10}=\;\frac{12}{60}=0.20 \text{gm}
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