Test Index

ICSE Class 10 Chemistry 2018 Paper

Show Para  Hide Para 
Aluminum carbide reacts with water according to the following equation :
Al4C3+12H2O→4Al(OH)3+3CH4\mathrm{Al}_4 \mathrm{C}_3 + 12 \mathrm{H}_2 \mathrm{O} \rightarrow 4 \mathrm{Al}(\mathrm{OH})_3 + 3 \mathrm{CH}_4
[Relative molecular weight of Al4C3=144\mathrm{Al}_4 \mathrm{C}_3 = 144; Al(OH)3=78]\mathrm{Al}(\mathrm{OH})_3 = 78]
© examsnet.com
Question : 56 of 80
Marks: +1, -0
What mass of aluminum hydroxide is formed from 12 g12\,\mathrm{g} of aluminum carbide?
Solution:  
Al4C3+12H2O→  4Al(OH)3+3CH4144 gm4×78 gm3×22.4\begin{array}{ccccccc} \mathrm{Al}_4\mathrm{C}_3 & + & 12\mathrm{H}_2\mathrm{O} & \rightarrow & \;4\mathrm{Al}(\mathrm{OH})_3 & + & 3\mathrm{CH}_4 \\ 144\,\mathrm{gm} & & & & 4\times 78\,\mathrm{gm} & & 3\times 22.4 \end{array}
If 144 gm  Al4C3144\,\mathrm{gm}\;\mathrm{Al}_4\mathrm{C}_3 forms 312 gm312\,\mathrm{gm} of Al(OH)3\mathrm{Al}(\mathrm{OH})_3 then 12 gm12\,\mathrm{gm} of Al4C3\mathrm{Al}_4\mathrm{C}_3 forms   4×78144×12\;\frac{4\times 78}{144} \times 12
=26 gm= 26\,\mathrm{gm}
© examsnet.com
Go to Question:
Prev Question
Next Question