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ICSE Class 10 Chemistry 2015 Paper

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Consider the following reaction and based on the reaction answer the questions that follow :
(NH4)2Cr2O7→heatN2(g)+4H2O(g)+Cr2O3(\mathrm{NH}_4)_2\mathrm{Cr}_2\mathrm{O}_7 \xrightarrow{\text{heat}} \mathrm{N}_2(g)+4\mathrm{H}_2\mathrm{O}(g)+\mathrm{Cr}_2\mathrm{O}_3
Calculate:
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Question : 61 of 85
Marks: +1, -0
the quantity in moles of nitrogen formed.
Solution:  
If 252gm252 {gm} of (NH4)2Cr2O7( {NH}_4) _2 {Cr}_2 {O}_7 release 28 g  "of"  N2{g} \;\text " of "\; {N}_2
Then 63g63 {g} of (NH4)2Cr2O7( {NH}_4) _2 {Cr}_2 {O}_7 release N2{N}_2 =  28×63/252=7g  "."  =\;{28 × 63}/{252}=7 {g} \;\text ". "\;
No. of moles of N2=  7/28=0.25{N}_2=\;{7}/{28}=0.25 moles.
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