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ICSE Class 10 Chemistry 2015 Paper

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Give balanced chemical equations for the following conversions :
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Question : 43 of 85
Marks: +1, -0
Ethanoic acid to ethyl ethanoate.
Solution:  
  CH3COOH+C2H5OH\;\mathrm{CH}_3\mathrm{COOH}+ \mathrm{C}_2\mathrm{H}_5\mathrm{OH}   →H2SO4 Conc.   CH3COOC2H5 ethyl ethanoate +H2O\;\xrightarrow[\mathrm{H}_2\mathrm{SO}_4]{\text{ Conc. }}\;\underset{\text{ ethyl ethanoate }}{\mathrm{CH}_3\mathrm{COOC}_2\mathrm{H}_5}+ \mathrm{H}_2\mathrm{O}
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