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CBSE Class 12 Physics 2023 Outside Delhi Set 3 Paper

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Question : 5 of 13
Marks: +1, -0
An electric dipole moment 2×108Cm2 \times 10^{-8} \,\mathrm{C} - \mathrm{m} in a uniform electric field experiences a maximum torque of 6×6 \times 104Nm10^{-4} \,\mathrm{N} - \mathrm{m}. The Magnitude of electric field is
Maximum torque experienced by the dipole is
τmax=PE\tau_{\max} = P E
or, 6×104=2×108×E6 \times 10^{-4} = 2 \times 10^{-8} \times E
E=3×104Vm1E = 3 \times 10^{4} \,\mathrm{Vm}^{-1}
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