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CBSE Class 12 Physics 2023 Outside Delhi Set 3 Paper

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Question : 12 of 13
Marks: +1, -0
A potential difference VV is applied across a conductor of length ll and cross-sectional area A. Briefly explain how the current density jj in the conductor will be affected if
(a) the potential difference VV is doubled. reduce
(b) the conductor were gradually stretched to its cross- sectional area to   A2\;\frac{A}{2} and then the same potential difference VV is applied across it.
Initial current =I=  VR=  Vρ  LA=  VAρL=I=\;\frac{V}{R}=\;\frac{V}{\rho \cdot \; \frac{L}{A}}=\;\frac{V A}{\rho L}
Initial current density =J=  VρL=J=\;\frac{V}{\rho L}
(a) Final current density =J=  2VρL=2J=J'=\;\frac{2V}{\rho L}=2J
So the current density becomes double.
(b) When area of cross section becomes   A2\;\frac{A}{2},
The length becomes 2L2L.
So, final current density =J=  VρL=J''=\;\frac{V}{\rho L'}
J=  V2ρL=  12JJ''=\;\frac{V}{2\rho L}=\;\frac{1}{2}J
So, the current density becomes half
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