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CBSE Class 12 Physics 2023 Outside Delhi Set 2 Paper

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Question : 10
Total: 13
A point object in air is placed symmetrically at a distance of 60‌cm in front of a concave spherical surface of refractive index 1.5 . If the radius of curvature of the surface is 20‌cm, find the position of the image formed.
Solution:     👈: Video Solution

For refraction from concave spherical surface,
‌
µ2
v
−‌
µ1
u
‌=‌
µ2−µ1
R
‌ or, ‌‌‌
1.5
v
−‌
1
(−60)
‌=‌
1.5−1
−20
‌ or, ‌‌‌
1.5
v
+‌
1
60
‌=−‌
0.5
20
‌ or, ‌‌‌
1.5
v
+‌
1
60
‌=−‌
1
40
‌‌ or, ‌‌‌
1.5
v
‌=−‌
1
40
−‌
1
60
‌∴‌v‌=−36‌cm
Image in formed in the medium where the object lies at a distance 36‌cm from point P.
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