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CBSE Class 12 Physics 2023 Outside Delhi Set 2 Paper

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Question : 6 of 13
Marks: +1, -0
A conductor of 10Ω10 \Omega is connected across a 6V6 \mathrm{V} ideal source. The power supplied by the source to the conductor is
P=V2RP = \frac{V^2}{R}
Or, P=6210P = \frac{6^2}{10}
∴ P=3.6W\therefore \ P = 3.6 \mathrm{W}
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