CBSE Class 12 Physics 2023 Outside Delhi Set 1 Paper

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Question : 11
Total: 35
A hydrogen atom makes a transition from n=5 to n=1 orbit. The wavelength of photon emitted is λ. The wavelength of photon emitted when it makes a transition from n=5 to n=2 orbit is
In 1st case
1
λ
=R[
1
12
1
52
]

or,
1
λ
=R[1
1
25
]
=R[
24
25
]

R=
25
24
×
1
λ

In 2nd case
1
λ
=R[
1
22
1
52
]

or,
1
λ
=R[
1
4
1
25
]
=R×
21
100

or,
1
λ
=
25
24
×
1
λ
×
21
100

or,
1
λ
=
21
96λ

λ=
96
21
λ
=
32
7
λ
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