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CBSE Class 12 Physics 2023 Outside Delhi Set 1 Paper

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Question : 6 of 35
Marks: +1, -0
A long straight wire of radius ' a ' carries a steady current I. The current is uniformly distributed across its area of cross-section. The ratio of magnitude of magnetic field
→
B
1 at ‌
a
2
 and
→
B
2 at distance 2a is
Solution:     👈: Video Solution
Magnetic field inside
B1=‌
µ0ir
2πa2
=‌
µ0i(a∕2)
2πa2
=‌
µ0i
4πa
 (Here, r=a∕2 )
Magnetic field outside =B2=‌
µ0i
2πr
=‌
µ0i
2π(2a)
=‌
µ0i
4πa
 (Here, r=2a )
So, The required ratio ‌
B1
B2
=1
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