CBSE Class 12 Physics 2023 Outside Delhi Set 1 Paper

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Question : 1
Total: 35
SECTION - A

The magnitude of the electric field due to a point charge object at a distance of 4.0m is 9‌
N
C
. From the same charged object the electric field of magnitude, 16‌
N
C
will be at a distance of
In 1‌st ‌ case,
‌E=‌
kq
r2

‌‌ Or, ‌‌‌9=‌
kq
42
‌
‌[r=4.0m]

‌∴‌‌kq=9×16
‌‌ In ‌2‌nd ‌‌ case, ‌
‌E′=‌
kq
(r′)2

‌ Or, ‌‌16‌=‌
9×16
(r′)2

‌ Or, ‌‌(r′)2=9
∴‌r′‌=3m
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