CBSE Class 12 Physics 2020 Outside Delhi Set 1 Paper

Question : 21

Total: 37

SECTION - B

Find the total charge stored in the network of capacitors connected between A and B as shown in figure:

Solution:

6µF and 3µF are connected in series. Hence their equivalent capacitance is 2µF.
4µF and 2µF are connected in series. Hence their equivalent capacitance is ‌

µF.
2µF and ‌

µF capacitors are connected in parallel.
So, the equivalent capacitance =‌

µF=‌

×10−6F
‌ We know ‌ Q‌=CV
C‌=‌

×10−6F
V‌=3V
∴ Q‌=‌

×10−6×3=10−5C

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