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CBSE Class 12 Physics 2019 Outside Delhi Set 2 Paper

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Question : 1 of 9
Marks: +1, -0
SECTION -A
Write the relation for the force acting on a charged particle qq moving with velocity v→\overset{\rightarrow}{v} in the presence of a magnetic field B→\overset{\rightarrow}{B}.
Solution:  
f→=q(v→×B→)\overset{\rightarrow}{f}=q\left(\overset{\rightarrow}{v}\times \overset{\rightarrow}{B}\right)
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